The condition that the chord xcoeA+ysinA=p of x2 +ye= a2 may substand a right angle at the center of the circle

Question

Arun · Answer

xcosα + ysinα = p

The perp ON from O to line has length |0+0−p|/√(cos²α+sin²α) = |p|

If chord of intersection AB subtends 90° at centre then ∠NOB=45°

From ΔNOB, cos(45°) = |p|/a → a=|p|√2 or a²=2p²

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The condition that the chord xcoeA+ysinA=p of x2 +ye= a2 may substand a right angle at the center of the circle

The condition that the chord xcoeA+ysinA=p of ^{x2 +ye= a2} may substand a right angle at the center of the circle

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The condition that the chord xcoeA+ysinA=p of x2 +ye= a2 may substand a right angle at the center of the circle

The condition that the chord xcoeA+ysinA=p of x2 +ye= a2 may substand a right angle at the center of the circle

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The condition that the chord xcoeA+ysinA=p of ^{x2 +ye= a2} may substand a right angle at the center of the circle