Polar of origin (0,0) w.r.t the circle x^2+y^2+2lambda x+2mu.y+c=0 touches the circle x^2+y^2=r^2 if....A. c=r(lambda^2+mu^2)B.r=c(lambda^2+mu^2)C.c^2=r^2(lambda^2+mu^2)D.r^2=c^2(lambda^2+mu^2)

Anvita Mahajan , 6 Years ago

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