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If the lines 3x – 4y + 4 = 0 and 6x - 8y - 7 = 0 are tangents to a circle, then the radius of the circle is

John Doe , 11 Years ago
Grade 12th pass
anser 1 Answers
Arun Kumar

Last Activity: 11 Years ago

Hello Student,
Since both lines are parallel & tangent to the circle. Then distance between these two lines must be the diameter of the circle.
Lines:
3x - 4y + 4 = 0
3x - 4y - \frac{7}{2} = 0
\frac{3}{4}d = \frac{|4-(-\frac{7}{2})|}{\sqrt{(3)^{2}}+(-4)^{2}} = \frac{\frac{15}{2}}{5} = \frac{3}{2}
R=d/2
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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