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If the line x+y-1=0 touches parabola y^2=kx, then k?
Hellow friends : The answer is here: The line x+y=1 touches the parabola y^2=kx or y^2=4.k/4 x ( Compare with standard eqn y^2=4ax) so a= k/4 and the condition of tangency for the line y=mx+c to a parabola y^2=4ax is that : c=a/m we ghave given c=1, m=-1, a=k/4 This implies 1=k/4(-1) => k=-4 k.k.Bisht
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