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Determine the equation of the circle with radius 4 and Centre (-2, 3).
Determine the equation of the circle with radius 4 and Centre (-2, 3).

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3 months ago Anand Kumar Pandey
2897 Points
```							Welcome to AskIITiansGiven that:Radius, r = 4, and center (h, k) = (-2, 3).We know that the equation of a circle with centre (h, k) and radius r is given as(x – h)^2+ (y – k)^2= r^2….(1)Now, substitute the radius and center values in (1), we getTherefore, the equation of the circle is(x + 2)^2+ (y – 3)^2= (4)^2x^2+ 4x + 4 + y^2– 6y + 9 = 16Now, simplify the above equation, we get:x^2+ y^2+ 4x – 6y – 3 = 0Thus, the equation of a circle with center (-2, 3) and radius 4 is x^2+ y^2+ 4x – 6y – 3 = 0Thanks
```
3 months ago
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