Ram Kushwah
Last Activity: 4 Years ago
The general equation of second degree can be written as:
ax²+2hxy +by²+2gx+2fy+c=0.......(1)
This equation can represent a pair of straight lines if:
abc +2fgh-af²-bg²-ch²=0..............(2)
The given equation is:
2x²+5xy +3y²+6x+7y+4=0
So a=2,b=3,c=4,f=7/2,g=3 and h=5/2
Putting these values in LHS of eqn(2)
2 ×3 ×4 + 2 × (7/2) × (3)(5/2) - 2 × (7/2)²- 3 × (3)²-4 × (5/2)²
=24+105/2 – 49/2 -27 -25
=24+(105-49)/2-52
= -28+(56/)/2
=-28+28
Thus we get
abc +2fgh-af²-bg²-ch²=0
Δ=0
Thus the given quadratic expression represents one pair of straight lines