Find the equation to the circle passing through t

Question

Find the equation to the circle passing through the points (0,a)(b,h) and having its centre on the axis of xPls give me full solution

poojitha · Accepted Answer

Let x^2+y^2+2gx+2fy+c=0 is our required circle equation with centre (-g,-f).since it passes through (0,a)and(b,h). substitute those points in circle equation.(0,a) a^2+2fa+c=0 is eq (1). (b,h) b^2+h^2+2gb+2fh+c=0 is eq (2).since centre lies on x-axis f=0.so from (1), c=-a^2.on substituting c and f values in eq(2),we get g = [a^2-(b^2+h^2)]/2bon substituting these values in circle equation we getb(x^2+y^2)+[a^2-(b^2+h^2)]x-a^2b=0 is our required circle equation.

Analytical Geometry> Find the equation to the circle passing t...

Find the equation to the circle passing through the points (0,a)(b,h) and having its centre on the axis of x
Pls give me full solution

Kamal Desai , 7 Years ago

poojitha

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Analytical Geometry> Find the equation to the circle passing t...

Find the equation to the circle passing through the points (0,a)(b,h) and having its centre on the axis of xPls give me full solution

Kamal Desai , 7 Years ago

poojitha

LIVE ONLINE CLASSES

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