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Compute the centre and radius of the circle 2x 2 + 2y 2 – x = 0

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2 months ago Anand Kumar Pandey
1412 Points
```							Welcome to AskIITiansGiven that, the circle equation is 2x^2+ 2y^2– x = 0This can be written as:⇒ (2x^2-x) + y2= 0⇒ 2{[x^2– (x/2)] +y^2} = 0⇒{ x^2– 2x(¼) + (¼)^2} +y^2– (¼)^2= 0Now, simplify the above form, we get⇒(x- (¼))^2+ (y-0)^2= (¼)^2The above equation is of the form (x – h)^2+ (y – k)^2= r^2Therefore, by comparing the general form and the equation obtained, we can sayh= ¼ , k = 0, and r = ¼.Thanks
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2 months ago
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