AO and DO are the bisector of angleA and angleD. Prove that angle AOD= 1/2 (angleB+angleC)

Question

Vikas TU · Answer

The question is incomplete though i am assuming that ABCD is any quadilateral. then A + B + C + D = 180 write B + C = 180 – (A + D) divide the whole eqn. by 2. (B+C)/2 = 90 – (A+D)/2.........(1) In triangle AOB also, AOB = 180 – 0.5*(A+D).......(2) Therefore from both the eqns. AOD= 1/2 (angleB+angleC) proved.

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AO and DO are the bisector of angleA and angleD. Prove that angle AOD= 1/2 (angleB+angleC)

AO and DO are the bisector of angleA and angleD. Prove that angle AOD= 1/2 (angleB+angleC)

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