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A straight line L is parpendicular to the line 5x-y=1. The area of the triangle formed by the line L and the coordinate axes is 5. Find the equation of the line L.
A straight line L is parpendicular to the line 5x-y=1. The area of the triangle formed by the line L and the coordinate axes is 5. Find the equation of the line L.

```
3 years ago

```							line parpendicular to given line is x + 5y = a. this can be written as x/a + y/(a/5) = 1area  = ½ * base * height = (1/2)* a * (a/5) = 5a^2 = 50a = +(50^(1/2) , – (50^(1/2)therefore equation of line is x + 5y = +(50^(1/2) and x + 5y = – (50^(1/2)
```
3 years ago
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