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Q:- If (2,3,5) is one end of a diameter of the sphere x2+y2+z2-6x-12y-2z+20=0,then the coordinates of the other end of the diameter are:
A. (4,9,-3)
B. (4,-3,3)
C. (4,3,5)
D. (4,3,-3)
the eqn of sphere can be written as
(x-3)2 + (y-6)2 + (z-1)2 = 26
center is ( 3, 6, 1)
as center is mid point, the other end of diameter is (4, 9, -3)
option A
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regards
Ramesh
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