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pls solve ths qutn
the radius of circle having center a (2,1)whose one of the chord is a diameter of the circle x2+y2-2x-6y+6=0 is.
Dear rohan
x2+y2-2x-6y+6=0
or
(x-1)2 +(y-3)2 =22
so p=√(2-1)2 +(1-3)2
=√5
so r =√5+4
=3
so equation of circle = (x-2)2 +(y-1)2 =9
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