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the length of a chord of circle is 4cm. If it's perpendicular distance from the centre is 1.5 cm, determine the radius of the circle
Let O be the Center.Let BC be the chord of 4 cmA is a point on chord BC so that OA is 1.5 cmOA is also perpendicular to chord BCSince, Perpendicular from the Center to the chord , bisect the chord ( a property of circle)BA = 2 cmNow, In triangle OAB by Pythagoras theoremOB^2 = OA^2 + BA^2OB^2 = 2^2 + 1.5^2= 4 + 2.25OB^2 = 6.25OB = 2.5 comSo radius of the circle = 2.5 cm
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