If (6,0),(0,6),(6,6) are the vertices of a triangle then distance between its circumcentre and centroid.

Dear pallavi bhardwaj

clearly the given triangle is a right angle triangle, right angle at (6,6)

centroid (4,4)

and circumcentre of a triangle lies on the mid point of hypt.

 circumcentre {(6+0)/2,(0+6)/2} =(3,3)

now distance ={(4-3)² +(4-3)²}^1/2

                          =√2

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