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`        (Roots of unity )xn-1=(x-1)p(x) where p(x) is a polynomial of degree n-1where p(x) is a0+a1x+...+an-1xn-1. I need to solve for the coefficients ai. My attempt at solving for coefficients:(xn-1)=a0x+a1x2+...+an-1xn-a0-a1x-...-an-1xn-1where I get a0=1 and an-1=1 I do not know if this is right. I don't think I solved for all the coefficients. Please help me. `
5 months ago

1672 Points
```							one easy way is tot simply divide x^n – 1 by x – 1 using the ususal division algorithm and then find out the coeffs. however, from the sum of GP formula, we know that 1+x+x^2+x^3+....+x^(n–1)= 1*(x^n – 1)/(x – 1)or xn-1=(x-1)(1+x+x^2+x^3+....+x^(n–1))hence we conclude that all the coefficients are equal to 1.
```
5 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions