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`        prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c `
2 years ago

subrat
61 Points
```							This can be solved using transformation of curves. Equation of chord when mid point is given is by T=S1 where T is the transformed equation and S1 is the value of curve when point is put into it. Transformation for xy=(x1y+xy1)/2. So,(2cy+3cx)/2 – c2 = 6c2 – c2 . Hence, the answer is 3x+2y=12c.
```
2 years ago
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