MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c
 
10 months ago

Answers : (1)

subrat
61 Points
							
This can be solved using transformation of curves. Equation of chord when mid point is given is by T=S1 where T is the transformed equation and S1 is the value of curve when point is put into it. Transformation for xy=(x1y+xy1)/2. So,
(2cy+3cx)/2 – c2 = 6c2 – c2 . Hence, the answer is 3x+2y=12c.
 
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 233 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details