prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c

Question

subrat · Answer

This can be solved using transformation of curves. Equation of chord when mid point is given is by T=S 1 where T is the transformed equation and S 1 is the value of curve when point is put into it. Transformation for xy=(x 1 y+xy 1 )/2. So, (2cy+3cx)/2 – c 2 = 6c 2 – c 2 . Hence, the answer is 3x+2y=12c.

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prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c

prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c

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prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c

prove that the equation of the chord of the hyperbola xy=c^2 which is bisected at the point (2c,3c) is 3x+2y=12c

1 Answers

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Other Related Questions on Algebra

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