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`        If x^2+2x+n-10>0 for all real number x, then which of the following conditions is true?A, n11`
3 years ago

moumi roy
91 Points
```							wi couldnot understand the question properly .i guess that u want condition on n for dis 2 happn.for dis discriminant(D) has 2 b less than zero as f(x) is >0 for all x.so 4-4(n-10)=4=n>11
```
3 years ago
moumi roy
91 Points
```							srry there is amistake in the calculation of the answerits D=b^2-4a*c=4-4(n-10)=111.hope dis the needed thing thank u
```
3 years ago
moumi roy
91 Points
```							again there is a mistake its not comming out properly .Idont know why.after typing on answer digit are mingled likethis.so this time i will write in words to make it proper.hope this is understandable.ans is that n must be greater than 11 as4-4(n-10) which is the discriminant is less than zero.so n comes out to be greater than 11
```
3 years ago
anjali
26 Points
```							Hey  see according to the question on any value of x the equation must be greater than zero. So its roots are imaginary .    On putting in the question we get 11
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions