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`        Find the value of 1/(22-1)+1/(42-1)+1/(62-1)..........1/(202-1)`
9 months ago

Vikas TU
11770 Points
```							Dear student Please follow the below link to get the ans of your queation .https://www.askiitians.com/forums/Algebra/find-the-value-of-1-2-2-1-1-4-2-1-1-6-2-1_257324.htmHope this helps Good Luck
```
9 months ago
2043 Points
```							r th term isar= 1/[(2r)^2 – 1)]= 1/[(2r – 1)(2r+1)]so, ar= 1/2(2r – 1) – 1/2(2r+1). if we take f(r)= 1/2(2r – 1) , then obviously f(r+1)= 1/2(2r+1).or ar= f(r) – f(r+1)so, we want to know a1 + a2 + a3 + …......... + a10= f(1) – f(2)+f(2) – f(3)​+f(3) – f(4)+........…....+f(9) – f(10)+f(10) – f(11)= f(1) – f(11)= ½ – 1/42= 10/21kindly approve :)
```
9 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions