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`        Find the value of 1/(22+-1)+1/(42-1)+1/(62-1).........+1/(202-1)`
6 months ago

Vikas TU
11138 Points
```							1/(2^2+-1)+1/(4^2-1)+1/(6^2-1).........+1/(20^2-1)= a^2 -b^ = (a+b)(a-b) Put this formula and multiply and divide by 2 = {2/(2+1)(2-1) + 2/(4+1)(4-1) +..... 2/(20-1)(20+1) ) }*1/2we can write numerator where there is 2 as (2+1)- (2-1) similarly we can also write 2 as (4+1)-(4-1) The equation will become [1/(2-1)  - 1/(2+1) +1/(4-1) -1/(4+1) ...1/(20-1) -1/(20+1) ] *1/2 On simplifying [1-1/3 + 1/3 -1/5 +1/5 ...........-1/19 -1/21 ] *1/2 Cancel all the term and simplify ans = 10/21
```
6 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions