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A man when he travels at 3 kmph he reaches the station 2 mins late. However when he travels at 4 kmph he reaches 2 mins quick. Find the distance the man has to travel?
Let his original time of reach be t mins after its start. And req. distance be x meters.
3 kmph=50 m/min
4kmph=200/3 m/min
A/Q
x = 50(t+2) -(1)
x=(200/3)(t-2) -(2)
From (1) and (2),we get
x= 800 m
Hope it helps.
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