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If a<0 and discriminant of ax2+2bx+c=0 is negative then value of det  a          b         ax+b        b          c         bx+c         = 0       ax+b    bx+c      0  Prove this plz........
If a<0 and discriminant of ax2+2bx+c=0 is negative then value of
det  a          b         ax+b
       b          c         bx+c         = 0
      ax+b    bx+c      0
Â
Prove this plz........
Dear Sohini, This is a very simple problem. It is given that a < 0 and 4b - 4ac > 0 0r a < 0 and b2 - ac > 0 Now, what you simply have to do is solve the given determinant using the properties which you have learnt and when you expand the equation you have to use a < 0 and b2 - ac > 0, use it and you will get the value of the determinant as 0.
Dear Sohini,
This is a very simple problem.
It is given that
a < 0 and 4b - 4ac > 0
0r a < 0 and b2 - ac > 0
Now, what you simply have to do is solve the given determinant using the properties which you have learnt and when you expand the equation you have to use a < 0 and b2 - ac > 0, use it and you will get the value of the determinant as 0.
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