If a<0 and discriminant of ax²+2bx+c=0 is negative then value of

det a b ax+b

b c bx+c = 0

ax+b bx+c 0

Prove this plz........

Dear Sohini,

This is a very simple problem.

It is given that

a < 0 and 4b - 4ac > 0

0r a < 0 and b² - ac > 0

Now, what you simply have to do is solve the given determinant using the properties which you have learnt and when you expand the equation you have to use a < 0 and b² - ac > 0, use it and you will get the value of the determinant as 0.