Find the sum of (1^4/1*3)+(2^4/3*5)+(3^4/5*7)+..................+ (n^4/(2n-1)(2n+1)).

Question

Sathya · Answer

If it continues up to m terms,thn is the ans i think Because its + and so on........ If u take common,thn it becomes Thn Its ans is

Swapnil Saxena · Answer

@ I cant understand ur solution. Pls simplify it... The solution fr the ques is here it is n[{2(n+1)(2n+1)}/3 + 1/(2n+1) +1]/16

Sathya · Answer

The answer for this is

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Find the sum of (1^4/13)+(2^4/35)+(3^4/5*7)+..................+ (n^4/(2n-1)(2n+1)).

Find the sum of (1^4/13)+(2^4/35)+(3^4/5*7)+..................+

(n^4/(2n-1)(2n+1)).

3 Answers

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Find the sum of (1^4/1*3)+(2^4/3*5)+(3^4/5*7)+..................+ (n^4/(2n-1)(2n+1)).

Find the sum of (1^4/1*3)+(2^4/3*5)+(3^4/5*7)+..................+ (n^4/(2n-1)(2n+1)).

3 Answers

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Find the sum of (1^4/13)+(2^4/35)+(3^4/5*7)+..................+ (n^4/(2n-1)(2n+1)).

Find the sum of (1^4/13)+(2^4/35)+(3^4/5*7)+..................+

(n^4/(2n-1)(2n+1)).