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WHAT IS THE REMAINDER WHEN 1!+2!+3!......n! is divided by 5??
Dear Shubham,
1! = 1
2! = 2
3! = 6
4! = 24
and all the factorials greater than 4 will be divided by 5
1!+2!+3!+4!+ (all the numbers are divided by 5 as all the factorials contain 5 )
1 +2 +6+24
33 is divided by 5 we get 3 as remainder
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jitender
hello shubham
since 1!+2!+3!+4! ends with 3(no is 33) and the rest no of factorials ends wth 0(as factorial of no exceding 4! have no 5and 2 whose multiplication ends with 0,ex5!=5*4*3*2*1 have 5 and 2)hence the whole ends with 3(0+3),so by divison by 5 we can logicaly see that 3 is the remainder..
hope this helps!
best of luck .
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