Dear pooja,
correct option is a)
solution
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(2x2-3x+1)(2x2+5x+1) =9x2
divide the equation by x^2 where x not equal to 0
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(2x-3+1/x)(2x+5+1/x) = 9
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let 2x+1/x = y put in the equation
(y-3)(y+5) = 9
y2+2 y - 24 = 0
solving the equation we get y = -6 and y = 4
so we get
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2x+1/x = -6 and
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2x+1/x = 4 we get
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2x2+6x+1=0 finding discriminant we get it as +ve so 2 real roots
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2x2-4x+1=0 and again finding discriminant we get it as +ve so 2 real roots so the total of 4 real roots
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