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if x=a+b,y=aω+bω2,z=aω2+bω, then find the value of xyz ?

mahima gerahwaal , 15 Years ago
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anser 1 Answers
Kevin Nash

Last Activity: 15 Years ago

Dear Mahima,

As you know that 'w' is the cube root of unity:

 so w3 = 1           &            w2+w + 1 = 0;

so 

         (a+b)(aw+bw2)(aw2+bw)

       = w2 (a+b)(a+bw)(aw+b)

        =(a+b)(a+bw)(aw3+bw2)

        =(a+b)(a+bw)(a+bw2) =a3+b3

  Thus your required answer is  : " a3+b3 "

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