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waht is the ph of solution?
plz solve this question as soon as possible.

manisha , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 6 Years ago

pH=pKa....+ …......log(salt/acid)As we are mixing equal volumes of the two solution, so the final concentration of NaOH as well as of acid would be ½ of the initial concentraton.Hence, pH=4.74+....log(0.1/0.1)=pKaHere we have assumed that the strong base dissociates completely(in general it is true), but the dissociation of weak acid is quite low.
 
pH = 1/2[pKw + pKa + log C]
= 1/2[14 +4.74 + log 0.1]
8.87

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