In the equilibrium SO2Cl2(g) - SO2(g) +Cl2(g) at 2000K and 10 atm pressure, %Cl2 = %SO2 = 40 (by volume)then calculate Kp ?

Question

Arun · Answer

Dear student SO2Cl2 = SO2 + Cl2 100 0 0 20 40 40 2 atm 4 atm 4 atm now calculate Kp you will get answer as Kp = 8

pranav · Answer

volume percent mean given mole percent thats mean it is mole fraction cl2 mole fraction is then =.4 then partial pressure =mole fraction * total pressure =.4*10=4 same for so2 for so2cl2 at eq P - 4 becoz we take so2cl2 initial partial pressure p now P -4+4+4 should equal to 10 here P =6 then at eq P -4 =2 now kp =4*4/2 =8

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In the equilibrium SO2Cl2(g) - SO2(g) +Cl2(g) at 2000K and 10 atm pressure, %Cl2 = %SO2 = 40 (by volume)then calculate Kp ?

In the equilibrium SO2Cl2(g) - SO2(g) +Cl2(g) at 2000K and 10 atm pressure, %Cl2 = %SO2 = 40 (by volume)then calculate Kp ?

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