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A small particle of mass 0.36 g rests on a horizontal turntable at a distance 25cm from the axis of spindle. The turntable is accelerated at a rate of Alpha = 1/3 Rad s^-2. The frictional force that the table exerts on the particle two seconds after the startup is
m=0.36g=0.36*10-3r=25cm=0.25mangular acceleration = 1/3 rad/s2Angular velocity after 2 s is v.ω = 0+(1/3)*2ω =2/3 rad/sSo, we know that the cancelling force with friction is the centripetal force which acts on the body, which is equal to mω2r.=0.36*10-3*(2/3)2(0.25)=0.04*10-3N
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