0

Guest

Courses New
  • Forum
  • AIPMT
  • In a random mating population an autosomal...

In a random mating population an autosomal recessive disorder is present in 60 individual out of 6000 what is the number of homozygous normal (AA) OFFSPRING in POPULATION

In a random mating population an autosomal recessive disorder is present in 60 individual out of 6000 what is the number of homozygous normal (AA) OFFSPRING
in POPULATION 

Question Image
Grade:12th pass

2 Answers

Arun
25758 Points
2 years ago
The ratio for BB:Bb:bb is 1:2:1.....so number of homozygous (BB) individuals is equal to no. of recessive (bb) individuals . AS BOTH RATIOS ARE EQUAL, NO. OF BB INDIVIDUALS=no. of bb individuals=60
so your answer is 60
Vikas TU
14149 Points
2 years ago
Dear student 
Since we believe that the homozygous recessive for this gene (q2) represents 4% (i.e. = 0.04), the square root (q) is 0.2 (20%). The frequency of the dominant allele. Answer: Since q = 0.2, and p + q = 1, then p = 0.8 (80%). The frequency of heterozygous individuals.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on AIPMT

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More