MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
A galvanic cell is set up from a zinc bar weighing 50 gram and 1.0 litre of 1.0 M, CuSO4 solution. How long would the cell run, assuming it delivers a steady current of 1.0 ampere
(a) 48hrs (b) 41hrs (ć) 21 hrs (d) 1 hrs
one year ago

Answers : (2)

Arun
23834 Points
							

As u know According to Faraday's 1st law if electrolysis….

W=Z×q or W=Z×I×t

We know Z ( electrochemical equivalent):—

Z= Equivalent weight / Faraday const. (F)

So, Equivalent wt of CuSO4 = molecular mass of CuSO4 valency.

Z= 159/2 = 79.5

Now we r given with,

W= 50g

I=1A

t=???

So put values in Formula and time will be founded

one year ago
arun kumar
9 Points
							
According to faraday 1st law of electrolysis
W=zit
W=50g
Molecular mass of cuso4 solution is 179
N factor 2
Z=159÷2=79.5
W=ZIt
50=79.5×1×t
T~0.63 ×3600(in sec)
T~21 hrs
7 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 728 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details