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A galvanic cell is set up from a zinc bar weighing 50 gram and 1.0 litre of 1.0 M, CuSO4 solution. How long would the cell run, assuming it delivers a steady current of 1.0 ampere(a) 48hrs (b) 41hrs (ć) 21 hrs (d) 1 hrs
As u know According to Faraday's 1st law if electrolysis….W=Z×q or W=Z×I×tWe know Z ( electrochemical equivalent):—Z= Equivalent weight / Faraday const. (F)So, Equivalent wt of CuSO4 = molecular mass of CuSO4 / valency.Z= 159/2 = 79.5Now we r given with,W= 50gI=1At=???So put values in Formula and time will be founded
As u know According to Faraday's 1st law if electrolysis….
W=Z×q or W=Z×I×t
We know Z ( electrochemical equivalent):—
Z= Equivalent weight / Faraday const. (F)
So, Equivalent wt of CuSO4 = molecular mass of CuSO4 / valency.
Z= 159/2 = 79.5
Now we r given with,
W= 50g
I=1A
t=???
So put values in Formula and time will be founded
According to faraday 1st law of electrolysisW=zitW=50gMolecular mass of cuso4 solution is 179N factor 2Z=159÷2=79.5W=ZIt50=79.5×1×tT~0.63 ×3600(in sec)T~21 hrs
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