Flag AIIMS MBBS> A wire suspended vertically from one of i...
question mark

A wire suspended vertically from one of it's end is stretched by attaching a weight of 200 N to the lower end. The weight stretches the wire by 1mm. Then the energy stored in the wire is
  • 0.1 J
  • 0.2 J
  • 10 J
  • 20 J

Abhishek Dogra , 7 Years ago
Grade 11
anser 1 Answers
Arun

As we learnt in

Work Done in Stretching Wire / Elastic P.E. -

=\frac{1}{2}\frac{YAl^{2}}{L}=\frac{1}{2}Fl

- wherein

L - Length of wire

l - increase in length

 

 We know that 

E=\frac{1}{2}\times F\times \Delta l

=\frac{1}{2}\times 200\times 10^{-3}J=0.1\ J

 
ApprovedApproved
Last Activity: 7 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments