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A source of power 600 kW emits photon which incident on a surface 2.5 m away out of which 50% is reflected back, what is the radiation pressure on the surface?
Intensity at 2.5 m way isI=600/(2.52)=96kW/m2Pressure p=2I/c where c is speed of light in free space=3×108m/sp=6.4×10^-4 N/m2please approve if helped.
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