A source of power 600 kW emits photon which incident on a surface 2.5 m away out of which 50% is reflected back, what is the radiation pressure on the surface?

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Susmita · Answer

Intensity at 2.5 m way is I=600/(2.5 2 )=96kW/m 2 Pressure p=2I/c where c is speed of light in free space=3×10 8 m/s p=6.4×10^-4 N/m 2 please approve if helped.

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A source of power 600 kW emits photon which incident on a surface 2.5 m away out of which 50% is reflected back, what is the radiation pressure on the surface?

A source of power 600 kW emits photon which incident on a surface 2.5 m away out of which 50% is reflected back, what is the radiation pressure on the surface?

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A source of power 600 kW emits photon which incident on a surface 2.5 m away out of which 50% is reflected back, what is the radiation pressure on the surface?

A source of power 600 kW emits photon which incident on a surface 2.5 m away out of which 50% is reflected back, what is the radiation pressure on the surface?

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