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V = 5+4x^2.force experienced by a negative charge of 1.5micro coloumb located at x=0.5m on solving we get E=-4f=qeso while solving do we want to consider q=-1.5 or 1.5a and why
Consider it +1.5 and not -1.5. Charge is taken with sign in Voltage calculations.And in the Calculation of force, whatever direction the force is, you can always visualize it without doing mathematics of sign.
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