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How many grams of conc. nitric acid solution should be used to prepare 250ml of 2.0 M HNO3? (1) 54.0 conc. HNO3 (2) 45.0 conc. HNO3 (3) 90.0 conc. HNO3 (4) 70.0 conc. HNO3
Dear student The required number of moles=( 250/1000)×2 =0.5 moles (no. of moles=molarity × volume) so,required mass of HNO3=0.5×63 =31.5 grams (given mass=no. of moles × molar mass) Given, 70 grams of HNO3 are present in 100 grams of the solution so,1 gram will be present in 100/70 grams of solution hence 31.5 grams will be present in (100/70)×31.5 grams of solution. so amount of concentrated nitric acid solution used is 45 grams. Regards Arun (askIITians forum expert)
i have a doubt ,where is it given that 70gm of hno3 is present in 100gm of solution?i am unable to find this.
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