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If a red blood cell (interior concentration of 0.9% salt) was placed into a test tube of 10% salt, what would happen to the red blood cell?

Siya Ann Siju , 5 Years ago
Grade 9
anser 3 Answers
Arun

Last Activity: 5 Years ago

In this case, the concentration of solution outside the blood cell is more and is thus called as hypertonic. It infers that the cell will shrink, as the water inside the cell moves outside making the cell flaccid. This process is called exosmosis. It happens because of the variation in the concentration gradient.
So, red blood cell would shrink as it loses water to the salt solution to the test tube

Sreevatsa Rajesh

Last Activity: 5 Years ago

 
the concentration of solution outside the blood cell is more and is thus called as hypertonic. It infers that the cell will shrink, as the water inside the cell moves outside making the cell flaccid. This process is called exosmosis. It happens because of the variation in the concentration gradient.
So, red blood cell would shrink as it loses water to the salt solution to the test tube
 
 

Yashraj

Last Activity: 5 Years ago

Red blood cells placed in a solution with a lower water concentration compared to their contents (eg 1.7 per cent salt solution) will lose water by osmosis and shrink. Water will diffuse from a higher water concentration inside the cell to a lower water concentration outside the cell.

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