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If a red blood cell (interior concentration of 0.9% salt) was placed into a test tube of 10% salt, what would happen to the red blood cell?

If a red blood cell (interior concentration of 0.9% salt) was placed into a test tube of 10% salt, what would happen to the red blood cell? 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 

Grade:9

3 Answers

Arun
25757 Points
3 years ago
In this case, the concentration of solution outside the blood cell is more and is thus called as hypertonic. It infers that the cell will shrink, as the water inside the cell moves outside making the cell flaccid. This process is called exosmosis. It happens because of the variation in the concentration gradient.
So, red blood cell would shrink as it loses water to the salt solution to the test tube
Sreevatsa Rajesh
34 Points
2 years ago
 
the concentration of solution outside the blood cell is more and is thus called as hypertonic. It infers that the cell will shrink, as the water inside the cell moves outside making the cell flaccid. This process is called exosmosis. It happens because of the variation in the concentration gradient.
So, red blood cell would shrink as it loses water to the salt solution to the test tube
 
 
Yashraj
915 Points
2 years ago
Red blood cells placed in a solution with a lower water concentration compared to their contents (eg 1.7 per cent salt solution) will lose water by osmosis and shrink. Water will diffuse from a higher water concentration inside the cell to a lower water concentration outside the cell.

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