Questions 18 complete sollution required for the question above .
pushkar , 6 Years ago
Grade
9 grade maths> Questions 18 complete sollution required ...
1 Answers
Arun
Last Activity: 6 Years ago
Dear Pushkar
take it as
a2+b2+c2-ab-bc-ca=0
Multiply both sides with 2, we get
2( a2 + b2 + c2 – ab – bc – ca) = 0
2a2 + 2b2 + 2c2 – 2ab – 2bc – 2ca = 0
(a2 – 2ab + b2) + (b2 – 2bc + c2) + (c2 – 2ca + a2) = 0
(a –b)2 + (b – c)2 + (c – a)2 = 0
Since the sum of square is zero then each term should be zero
(a –b)2 = 0, (b – c)2 = 0, (c – a)2 = 0
(a –b) = 0, (b – c) = 0, (c – a) = 0
a = b, b = c, c = a
a = b = c.
2a2 + 2b2 + 2c2 – 2ab – 2bc – 2ca = 0
(a2 – 2ab + b2) + (b2 – 2bc + c2) + (c2 – 2ca + a2) = 0
(a –b)2 + (b – c)2 + (c – a)2 = 0
Since the sum of square is zero then each term should be zero
(a –b)2 = 0, (b – c)2 = 0, (c – a)2 = 0
(a –b) = 0, (b – c) = 0, (c – a) = 0
a = b, b = c, c = a
a = b = c.
therefore c+a/b=2
Regards
Arun
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