Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping

Prove that 2 + root6 is irrational or prove that 3 + 8 is irrational

Prove that 2 + root6 is irrational or prove that 3 + 8 is irrational


2 Answers

Darpan Verma
58 Points
4 years ago
Subtract 3 from 3+√8.your answer will be √8.we can also write √8 as 2√ divide it by will be √2 which is whole term is irrational.
45 Points
4 years ago
I will answer 3+√6 firstLet 3+√6=p/q ;q≠0;p and q are co-prime integers3+√6=p/q√6=p/q -3√6=p-3q /qHera p-3q /q is rationalLet√6=a/b (a rational);b≠0;a and b are co-prime integers √6=a/bSquaring both sides (√6)^2=(a/b)^26=a^2/b^2b^2=a^2/6 this implies 6 divides a^2 as well as aLet a=6cSquaring both sides a^2=(6c)^2a^2=36c^2Substitutingb^2=36c^2/6b^2=6c^2c^2=b^2/6 this implies 6 divides b^2 as well as b From above 6 is a common factor of both a and b. This is a contradiction because of our wrong assumption that √6 is rationalHence √6 is irrational√6=p-3q/qIrrational=rational Which is a contradiction. This happen because of our wrong assumption that 3+√6 is rational Hence 3+√6 is irrational. THE OTHER QUESTIONS answer3+8 is rational

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy


Get your questions answered by the expert for free