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Grade 11,

Plazzzzzzzzzzzoooooooooo9ooooooooooooo solve question number 52

Plazzzzzzzzzzzoooooooooo9ooooooooooooo solve question number 52

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Grade:11

1 Answers

Aditya Gupta
2081 Points
5 years ago
so obviously we know that (y+z)^3= y^3+z^3+3yz(y+z)
so, x^3= 4a+ 3b^2/3*x
or x^3 – 3b^2/3*x= 4a
x^3 – 3b^2/3*x+9a= 4a+9a= 13a

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