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Grade 12th pass9 grade maths

Diagonals AC and BD of a quadrila.teral ABCD intersect each other at P. Show that ar(APBJ x ar(CPDJ = ar(APDJ x ar(BPC). [Hint: From A and C, draw perpendi.culars to BD.]

Profile image of Harshit Singh
5 Years agoGrade 12th pass
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1 Answer

Profile image of Pawan Prajapati
5 Years ago
. ar(APB) x ar(CPD) = (ix BP x AL ) (ix PD xCM ) = !. x BP x DP x AL x CM 4 And ar(APD) x ar(BPC) .•.(i) D = !_ x BP x DP x AL x CM ...(ii) From (i) and (ii), we get A B ar(APB) x ar(CPD) = ar(APD) x ar(BPC).