Flag 9 grade maths> Diagonals AC and BD of a quadrila.teral A...
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Diagonals AC and BD of a quadrila.teral ABCD intersect each other at P. Show that ar(APBJ x ar(CPDJ = ar(APDJ x ar(BPC). [Hint: From A and C, draw perpendi.culars to BD.]

Harshit Singh , 4 Years ago
Grade 12th pass
anser 1 Answers
Pawan Prajapati

Last Activity: 4 Years ago

. ar(APB) x ar(CPD) = (ix BP x AL ) (ix PD xCM ) = !. x BP x DP x AL x CM 4 And ar(APD) x ar(BPC) .•.(i) D = !_ x BP x DP x AL x CM ...(ii) From (i) and (ii), we get A B ar(APB) x ar(CPD) = ar(APD) x ar(BPC).

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