7. ABCD is a rhombus. Show that diagonal AC bisects L A as well as L C and diagonal BD bisects L B as well as LD.

Consider triangles ADC and ABC, AD = AB [Sides of a rhombus] AC is common. CD = CB .. 4ADC 4ABC => L DAC = L BAC [Sides of a rhombus] [SSS] D ..•(i) [CPCTJ and L DCA = L BCA ...(ii) [CPCTJ Hence AC bisects LA and LC. Similarly, by taking triangles BAD and BCD, we can show that BD bisects LB and LD.