Pawan Prajapati
Last Activity: 4 Years ago
Consider the equation x - 2y = 4 ...(A)
(i) For (0, 2), substituting x = 0, y = 2 in (A), we get
0 - 4 = 4 => - 4 = 4, not true.
Hence, (0, 2) is not a solution.
(ii) For (2, 0), substituting x = 2, y = 0 in (A), we get 2 - 0 = 4 => 2 = 4, not true.
Hence, (2, 0) is not a solution.
(iii) For (4, 0), substituting x = 4, y = 0 in (A), we get
4 - 0 = 4 => 4 = 4, true.
Hence, (4, 0) is a solution.
(iv) For ( J2 , 4../2 ), substituting x = .J2 , y = 4 .J2 in (A), we get •
.J2 - 8.J2 = 4 => - 7 J2 = 4, not true.
Hence, ( J2 , 4 ../2 ) is not a 8olution.
(v) For (1, 1), substituting x = 1, y = 1 in (A), we get
• 100 1- 2 = 4 => - 1= 4, not true.
Hence, (1, 1) is not a solution.