11. Eleuen bags of wheat {four, each marked 5 kg, actually contained the following weights of flour ( in kg): 491 5.05 5.

Question

Pawan Prajapati · Answer

Tutal number of bags is 11. Number of bags containing flour (in kg) more than 6 kg is 7, i.e., 5.05, 5.08, 5.03, 5.06, 5.08, 5.04, 5.07. :. Probability that a bag chosen at random contains more than 5 kg of flour = 7

Ram Kushwah · Answer

Question: Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg): 4.97, 5.05,5.08,5.03, 5.00 ,5.06,5.08 ,4.98, 5.04,5.07 ,5.00 Find the probability that any of these bags chosen at random contains more than 5 kg of flour. Solution: Here Total number of bags=11 Thus total No of events=11 We see that no of bags with weight of more than 5 kgs =7 So favoring events=7 Hence the probability =Favoring events/ Total events =7/11 Pl aprove Thanks

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11. Eleuen bags of wheat {four, each marked 5 kg, actually contained the following weights of flour ( in kg): 491 5.05 5. Find the probability that any of these bags chosen. at random contains more than 5 kg of flour.

11. Eleuen bags of wheat {four, each marked 5 kg, actually contained the following weights of flour ( in kg):
491 5.05 5.Find the probability that any of these bags chosen. at random contains more than 5 kg of flour.

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