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for what value of , the function f(x)=2cos2x-cos4xattains its absolute minimum in [0,pi]
f`(x) = -4sin 2x + 4sin4x = 0sin 2x = sin 4xsin 2x = 0 , or , cos 2x = 1/2x = 0,90 or x = 30f``(x) = -8cos2x + 16cos4xHence, absolute minimum is at x = 90 which is f(x) = -3ThanksBharat Bajajaskiitians facultyIIT Delhi
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