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159/128 Terminating or non terminating decimal expansion

159/128
Terminating or non terminating decimal expansion

Grade:10

5 Answers

Arun
25757 Points
3 years ago
Dear student
 
For this we have to check first denominat128 = 2^7
 
As denominator is in the form of 2^m  * 5^n
Where m = 7 and n = 0
hence this is terminating decimals
Vikas TU
14149 Points
3 years ago
Dear student
Here, the factors of the denominator 128 are are 5^0 × 2^7 which is in the form 2ⁿ 5^m .
159 * 5^7 /(2*5)^7
12421875/10000000
1.2421875
Hope this helps 
Good Luck
 
Sayantan Garai
117 Points
3 years ago
First, simplify a factor to p/q form, where p & q এই mutual primes.
Now, factorise the denominator. 
If we get only 1, 2 and 5 as the factors of the denominator, then the fraction is terminating.
 
Here, 159/128's denominator 128 gives 2^7.
As there is only 2 's in the factorization of denominator, the fraction is terminating. 
Sayantan Garai
117 Points
3 years ago
Sorry এই is equal to are. It is a problem in my keyboard that language automatically changes... 
Sorry
Yashraj
915 Points
3 years ago
denominator is the form of  2 raise to m multiplied by 5 raise to n so it is terminating 
hope this concept helps
 

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