# 159/128Terminating or non terminating decimal expansion

Arun
25757 Points
3 years ago
Dear student

For this we have to check first denominat128 = 2^7

As denominator is in the form of 2^m  * 5^n
Where m = 7 and n = 0
hence this is terminating decimals
Vikas TU
14149 Points
3 years ago
Dear student
Here, the factors of the denominator 128 are are 5^0 × 2^7 which is in the form 2ⁿ 5^m .
159 * 5^7 /(2*5)^7
12421875/10000000
1.2421875
Hope this helps
Good Luck

Sayantan Garai
117 Points
3 years ago
First, simplify a factor to p/q form, where p & q এই mutual primes.
Now, factorise the denominator.
If we get only 1, 2 and 5 as the factors of the denominator, then the fraction is terminating.

Here, 159/128's denominator 128 gives 2^7.
As there is only 2 's in the factorization of denominator, the fraction is terminating.
Sayantan Garai
117 Points
3 years ago
Sorry এই is equal to are. It is a problem in my keyboard that language automatically changes...
Sorry
Yashraj
915 Points
3 years ago
denominator is the form of  2 raise to m multiplied by 5 raise to n so it is terminating
hope this concept helps