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159/128Terminating or non terminating decimal expansion
Dear student For this we have to check first denominat128 = 2^7 As denominator is in the form of 2^m * 5^nWhere m = 7 and n = 0hence this is terminating decimals
Dear studentHere, the factors of the denominator 128 are are 5^0 × 2^7 which is in the form 2ⁿ 5^m .159 * 5^7 /(2*5)^712421875/100000001.2421875Hope this helps Good Luck
First, simplify a factor to p/q form, where p & q এই mutual primes.Now, factorise the denominator. If we get only 1, 2 and 5 as the factors of the denominator, then the fraction is terminating. Here, 159/128's denominator 128 gives 2^7.As there is only 2 's in the factorization of denominator, the fraction is terminating.
Sorry এই is equal to are. It is a problem in my keyboard that language automatically changes... Sorry
denominator is the form of 2 raise to m multiplied by 5 raise to n so it is terminating hope this concept helps
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