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Two waves represented by y= a sin(wt - kx) and y= a cos(wt - kx) are superposed The resultant wave will have an amplitude?
Two waves represented by y= a sin(wt - kx) and y= a cos(wt - kx) are superposed The resultant wave will have an amplitude?

```
3 years ago

```							the 2nd wave can be written as y2=Asin(wt-kx+pi/2)Now by superposition principle, the resultant wave is y=y1+y2y=A[sin(wt-kx)+sin(wt-kx+pi/2)]   =2Acos(pi/4)sin(wt-kx+pi/4)       (Transformation formula used)This wave equation is telling us that the amplitude of the resultant wave is 2Acos(pi/4) and the the phase angle of the wave is pi/4 , while frequency remaining constant.
```
3 years ago
```							Dear Student,Please find below the solution to your problem.Given, y1 ​= asin(ωt-kx)y2 ​= acos(ωt-kx)or y2​ = asin(ωt-kx+2π​)Phase difference of two waves = 2π​∵ Resultant amplitudeR = a2 + a2 + 2aacosϕ​= a2 + a2 + 2a2^cos2π​​= 2a^2​     (∵cos2π​=0)R = 2​a.y1= asin⁡(ωt-kx)Thanks and Regards
```
6 months ago
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