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Pls help.. Answer is three.... Shouldn't it be five....??? Pls help..Answer is three.... Shouldn't it be five....???
For Maxima it's knowndSinθ = nλGiven d=2λSo 2λsinθ = nλ2sinθ=nValue of sinθ varies from -1 to +1 so there total five possibilities for Maxima interference for n = -2,-1,0,+1,+2
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