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Grade: 12

                        

Pls help.. Answer is three.... Shouldn't it be five....???

6 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
8407 Points
							576-677_IMG_20200415_122541.jpg
						
6 months ago
Arun
24742 Points
							
For Maxima it's known
dSinθ = nλ
Given d=2λ
So 2λsinθ = nλ
2sinθ=n
Value of sinθ varies from -1 to +1 so there total five possibilities for Maxima interference for n = -2,-1,0,+1,+2
6 months ago
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