Question icon
Grade 12th passWave Optics

Minimum thickness of mica sheet having u=3/2 which should be placed in front of one of the slit in YDSE to reduce the intensity at center of screen to half the maximum intensity is.. . ........ ANS:lambda/2

Profile image of  Pawan joshi
7 Years agoGrade 12th pass
Answers icon

1 Answer

Profile image of Vikas TU
7 Years ago
For the refractive index 3/2 mica intoduced,
the path difference becomes,
n*lamda = (u-1)*t
n*lamda = (3/2 – 1)*t
t = 2*n*lamda’
 Now ntensity is inversely proportional to the wavelength.
To reduce the intesity to the half, i.e. for
I = 1/lamda
I/2 = 1/lamda’
lamda’ /lamda = 2
or
lamda’ = lamda/2
 
The wavelngth should become twice of the initial value.
t = lamda/2 would be the thikness for n=1.