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Grade: 12

                        

If the intensity of sound is doubled, by how many decibels does the sound level increase?

3 years ago

Answers : (1)

Arun
24742 Points
							

If the intensity of sound in watts per square metre is I, then the intensity level in decibel (dB) is given by

dB= 10 log(I/I•),

Where the base of logarithm is 10,

I•=10^-12 watt per square metre( roughly the intensity at which audible sound can be heard)

On the decibel scale the pain threshold is 1 watt per square metre and on decibel scale is:

dB= 10 log(1 watt per square metre/10^-12 watt per square metre)

dB= 10 log ( 1/10^-12)= 10* log (10^12)=10*12=120 dB

In the given problem

dB= 10 log ( 2 I/I)= 10* log 2=10*0.3010=3.010dB

3 years ago
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