Figure depicts a simplistic optical fiber: a plastic core (n1 = 1.58) is surrounded by a plastic sheath (n2 = 1.53). A light ray is incident on one end of the fiber at angle θ. The ray is to undergo total internal reflection at point A, where it encounters the core – sheath boundary. (Thus there is no loss of light through that boundary.) What is the maximum value of θ that allows total internal reflection at A?

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Saurabh Koranglekar · Answer

Dear student It is critical angle Theta = arcsin ( n2/n1) Regards

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