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Figure depicts a simplistic optical fiber: a plastic core (n1 = 1.58) is surrounded by a plastic sheath (n2 = 1.53). A light ray is incident on one end of the fiber at angle θ. The ray is to undergo total internal reflection at point A, where it encounters the core – sheath boundary. (Thus there is no loss of light through that boundary.) What is the maximum value of θ that allows total internal reflection at A?

Anirvan Goswami , 7 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

Dear student

It is critical angle

Theta = arcsin ( n2/n1)

Regards

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