At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is 1)pi/8 2)pi/4 3)pi/2 4)pi

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Vikas TU · Answer

At the first minima => a sinѲ = nƛ => a sinѲ = ƛ Then Phase diference =dx1/wavelength x 2pi = a/2 sinѲ/ ƛ x2pi = ƛ/2/ ƛ * 2 pi = pi

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At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is 1)pi/8 2)pi/4 3)pi/2 4)pi

At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is
1)pi/8
2)pi/4
3)pi/2
4)pi

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At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is 1)pi/8 2)pi/4 3)pi/2 4)pi

At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is1)pi/8 2)pi/43)pi/24)pi

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At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is
1)pi/8
2)pi/4
3)pi/2
4)pi