Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point of the slit is 1)pi/8 2)pi/4 3)pi/2 4)pi

At first minimum adjacent to the centraĺ maximum of a single slit of diffraction pattern the phase difference between huygen's wavelet from the edge of the slit and the wavelet from the mid point  of the slit is
1)pi/8 
2)pi/4
3)pi/2
4)pi
 

Grade:12th pass

1 Answers

Vikas TU
14149 Points
4 years ago
At the first minima
=>   a sinѲ = nƛ
=>  a sinѲ = ƛ
Then Phase diference =dx1/wavelength x 2pi
                            = a/2 sinѲ/ ƛ x2pi
                            = ƛ/2/ ƛ * 2 pi
                               = pi
 
 
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free